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6r^2-9r-4=0
a = 6; b = -9; c = -4;
Δ = b2-4ac
Δ = -92-4·6·(-4)
Δ = 177
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{177}}{2*6}=\frac{9-\sqrt{177}}{12} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{177}}{2*6}=\frac{9+\sqrt{177}}{12} $
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